Ask Question
3 April, 09:05

A gas container in a thick walled balloon. when the pressure changes from __kPa to 114kpa, the volume changes from 0.654L to 1.32 L and the temperature changes from 596 K to 715 k

+4
Answers (1)
  1. 3 April, 09:27
    0
    To solve this we assume that the gas is an ideal gas. Then, we can use the ideal gas equation which is expressed as PV = nRT. At number of moles the value of PV/T is equal to some constant. At another set of condition of temperature, the constant is still the same. Calculations are as follows:

    P1V1/T1 = P2V2/T2

    P1 = P2V2T1/T2V1

    P1 = (114) (1.32) (596) / (715) (.654)

    P1 = 191.80 kPa
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “A gas container in a thick walled balloon. when the pressure changes from __kPa to 114kpa, the volume changes from 0.654L to 1.32 L and the ...” in 📙 Chemistry if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers