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30 April, 15:05

what is the amount of heat, in joules, required to increase the temperature of a 49.5-gram sample of wanted from 22c to 66c

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  1. 30 April, 18:46
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    the amount of heat, in joules, required to increase the temperature of a 49.5-gram sample of wanted from 22°c to 66°c is 9.104 Joules.

    Explanation:

    The answer can be calculated using the formula

    Q = mCрΔT

    where

    Q is the amount of heat required in joules to raise the temperature.

    m is the mass of the sample in Kg.

    Cp is the specific heat of the sample in J/Kg°C.

    ΔT is the change in temperature required.

    Here, m = 49.5-gram = 0.0495 kg

    Cp = 4.18 J/Kg°C (for water)

    T₁ = 22°C; T₂ = 66°C

    ΔT = 66 - 22 = 44

    Substituting values in Q = mCрΔT

    Q = (0.0495) (4.18) (44)

    Q = 9.104 J
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