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28 November, 11:47

Methylhydrazine, CH6N2, is commonly used as a liquid rocket fuel. The heat of combustion of methylhydrazine is - 1.30 * 103 kJ/mol. How much heat is released when 202.7 g of methylhydrazine is burned

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  1. 28 November, 14:03
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    There is 5720 J of heat released.

    Explanation:

    Step 1: Data given

    Molar mass of CH6N2 = 46.07 g/mol

    The heat of combustion of methylhydrazine is - 1.30 * 103 kJ/mol

    Mass of methylhydrazine = 202.7 grams

    Step 2: Calculate number of moles

    Moles CH6N2 = mass of CH6N2 / Molar mass CH6N2

    Moles CH6N2 = 202.7 grams / 46.07 g/mol

    Moles CH6N2 = 4.4 moles

    Step 3: Calculate heat released when 202.7 grams of CH6N2 is burned

    q = 1300 J/mol * 4.4 moles

    q = 5720 J

    (Since there is heat released, ΔH = negative)

    There is 5720 J released.
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