What is the molarity of a solution that has 2.0 mol of MgF2 dissolved in enough water to make 1.29 L of solution?

The molarity of MgF2 is 1.55 M

Explanation:

Step 1: Data given

Number of moles MgF2 = 2.0 moles

Volume of solution = 1.29 L

Molar mass MgF2 = 62.3 g/mol

Step 2: Calculate molarity of the MgF2 solution

Molarity MgF2 = moles MgF2 / volume solution

Molarity MgF2 = 2.0 moles MgF2 / 1.29 L

Molarity MgF2 = 1.55 mol/L = 1.55 M

The molarity of MgF2 is 1.55 M

[MgF₂] = 1.55 M

Explanation:

Molarity → mol/L

A sort of concentration where are indicated the moles of solute contained in 1L of solution

Moles of solute: 2 moles

Volume of solution 1.29L

M = 2 mol / 1.29L = 1.55M