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Chemistry
Nadia Waters
4 January, 16:15
How many atoms are present in 20.9 g of titanium
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Gerald
4 January, 18:31
0
atoms Ti = 2.193 E23 atoms
Explanation:
1 mol ≡ 6.022 E23 atoms mm Ti = 47.867 g/mol
⇒ atoms Ti = (20.9 g Ti) * (mol/47.867 g) * (6.022 E23 atoms/mol)
⇒ atoms Ti = 2.193 E23 atoms
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