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16 October, 11:42

Suppose there is 1.00 L of an aqueous buffer containing 60.0 mmol of acetic acid (p K a = 4.76) and 40.0 mmol of acetate. Calculate the pH of this buffer.

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  1. 16 October, 14:27
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    pH = 4.584

    Explanation:

    CH3COOH ↔ CH3COO - + H3O+

    for buffer solution, Henderson-Hauselbach equation:

    pH = pKa + log [A-]/[HA]

    ∴ HA: CH3COOH

    ∴ pKa = 4.76

    ⇒ [CH3COOH] = ((60.0 mmol) * (mol/1000 mmol)) / (1.00 L) = 0.06 M

    ⇒ [CH3COO-] = ((40.0 mmol) * (mol/1000 mmol) / (1.00 L) = 0.04 M

    ⇒ pH = 4.76 + log (0.04/0.06)

    ⇒ pH = 4.76 + ( - 0.176)

    ⇒ pH = 4.584
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