If 125 mL of a 1.1 M glucose solution is diluted to 500.0 mL, what is the molarity of the diluted solution? Express your answer using two significant figures.

0.28M

Explanation:

From the question given, we obtained the following information:

C1 = 1.1 M

V1 = 125mL

V2 = 500mL

C2 = ?

Using the dilution formula C1V1 = C2V2, we can easily find the molarity of the diluted solution as follows:

C1V1 = C2V2

1.1 x 125 = C2 x 500

Divide both side by 500

C2 = (1.1 x 125) / 500 =

C2 = 0.28M