Sulfuric acid reacts with aluminum hydroxide by double replacement. if 34 g of sulfuric acid react with 33 g of aluminum hydroxide, identify the limiting reactant.

Question

Chemistry

Ashley Ellis

31 December, 21:14

Sulfuric acid reacts with aluminum hydroxide by double replacement. if 34 g of sulfuric acid react with 33 g of aluminum hydroxide, identify the limiting reactant.

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Ethan Sandoval · Answer 1

Answer is: sulfuric acid is the limiting reactant.

Chemical reaction: 3H₂SO₄ + 2Al (OH) ₃ → Al₂ (SO₄) ₃ + 6H₂O.

m (H₂SO₄) = 34 g.

n (H₂SO₄) = m (H₂SO₄) : M (H₂SO₄).

n (H₂SO₄) = 34 g : 98 g/mol.

n (H₂SO₄) = 0,346 mol.

m (Al (OH) ₃) = 33 g.

n (Al (OH) ₃) = 33 g : 78 g/mol.

n (Al (OH) ₃) = 0,423 mol.

From chemical reaction: n (H₂SO₄) : n (Al (OH) ₃) = 3 : 2.