How many grams of F are in 12.56 g of SF6? h.

9.80 g

Explanation:

The molecular mass of the atoms mentioned in the question is as follows -

S = 32 g / mol

F = 19 g / mol

The molecular mass of the compound, SF₆ = 32 + (6 * 19) = 146 g / mol

The mass of 6 F = 6 * 19 = 114 g / mol.

The percentage of F in the compound =

mass of 6 F / total mass of the compound * 100

Hence,

The percentage of F in the compound = 114 g / mol / 146 g / mol * 100

78.08 %

Hence, from the question,

In 12.56 g of the compound,

The grams of F = 0.7808 * 12.56 = 9.80 g