A jogger runs with a velocity of 3.109 m/s NW over a period of 53.10 minutes. If the jogger initially ran SE for 911.9 m before changing direction and heading NW, what total distance did he run?

Question

Chemistry

Conner Allison

12 May, 04:10

A jogger runs with a velocity of 3.109 m/s NW over a period of 53.10 minutes. If the jogger initially ran SE for 911.9 m before changing direction and heading NW, what total distance did he run?

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Answers (1)

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Harold Mccall · Answer 1

The distance cover by Jogger before heading NW is 8993.3 meters

Explanation:

Given as:

Jogger initial distance in south east direction = 911.9 meters

The speed of Jogger in north west direction is 3.109 m/s

The time taken to cover distance in north west direction is 53.10 minutes

Or, the time taken = 53.10 * 60 sec

I. e Time taken = 3186 seconds

So, the Distance cover in north west direction = Speed * time

or, The Distance cover in north west direction = 3.109 mps * 3186 sec

Or, = 9905.2 meters

So. before heading NW, the distance cover = 9905.2 m - 911.9 m = 8993.3 meters

Hence The distance cover by Jogger before heading NW is 8993.3 meters Answer