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7 May, 12:00

An experiment calls for 0.0284 g of potassium hydroxide, KOH. How many milliliters of 0.0200 M KOH are required

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  1. 7 May, 12:09
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    We need 25.3 mL of KOH

    Explanation:

    Step 1: Data given

    Mass of potassium hydroxide (KOH) = 0.0284 grams

    Molarity of KOH = 0.0200 M

    Molar mass of KOH = 56.106 g/mol

    Step 2: Calculate moles of KOH

    Moles KOH = mass KOH / molar mass KOH

    Moles KOH = 0.0284 grams / 56.106 g/mol

    Moles KOH = 5.06 * 10^-4 moles

    Step 3: Calculate volume needed

    Molarity KOH solution = moles KOH / volume

    Volume = moles KOH / molarity KOH

    Volume = 5.06 * 10^-4 moles / 0.0200 M

    Volume = 0.0253 L = 25.3 mL

    We need 25.3 mL of KOH
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