What is the mass of 2.23 times 10^23 atoms of sulfur

The atomic mass of sulfur is 32.07 g/mole.

1 mole of sulfur contains 6.022 * 10^23 atoms

But 1 mole is equal to 32.07 g

Therefore;

6.022 * 10^23 atoms = 32.07

Thus; 2.23 * 10^23 atoms = ?

= (2.23 * 10^23 * 32.07) / 6.022*10^23

= 11.876 g