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10 October, 00:13

N2 (g) + 3H2-> 2NH3 (g) How many grams of ammonia (NH3) can be produced from the reaction of 28.0 g of N2 and 25.0 g of H2?

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  1. 10 October, 01:29
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    34 g of NH₃ were produced in the reaction

    Explanation:

    N₂ (g) + 3H₂ (g) → 2NH₃ (g)

    Moles of N₂ → 28 g / 28 g/m = 1 mol

    Moles of H₂ → 25g / 2 g/m = 12.5 moles

    Clearly, the limiting is the nitrogen.

    1 mol of N₂ produced 2 moles of ammonia

    So, If I have 1 mol, I'll produce the same amount

    2 moles of NH₃ = Mol. Molar mass

    2 m. 17 g/m = 34 g
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