Sodium reacts with water according to the reaction:

2Na (s) + 2H2O (l) →2NaOH (aq) + H2 (g)

Identify the oxidizing agent.

a) H2O (l)

b) NaOH (aq)

c) Na (s)

d) H2 (g)

a. H₂O. This is the oxidizing agent. It was reduced to oxidize the Na.

Explanation:

A redox reaction: 2Na (s) + 2H₂O (l) →2NaOH (aq) + H₂ (g)

Sodium changes from 0 (oxidation state) to + 1. It has been oxidized.

It has released and electron.

H⁺ from water has gained an electron, so it changed the oxidation state from + 1 to 0. As the oxidation state has decreased, the element was reduced. So it won electrons.

In conclussion the water was reduced to hydrogen at ground state, to oxidized the Na. That's why H₂O is the oxidizing agent.

Answer: A) H20 (I)

Explanation:

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