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21 May, 22:40

The analysis of a compound gives the following percent composition by mass: C: 52.14 percent; H: 9.946 percent; S: 12.66 percent; O: 25.26 percent. What is its molecular formula given that its molar mass is 253.4 g?

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  1. 22 May, 01:27
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    C11H25SO4

    Explanation:

    The total mass of the compound is 253.4 g, so, the mass of each element will be:

    C: 52.14% of 253.4 = 0.5214x253.4 = 132.12 g

    H: 9.946% of 253.4 = 0.09946x253.4 = 25.20 g

    S: 12.66% of 253.4 = 0.1266x253.4 = 32.08 g

    O: 25.26% of 253.4 = 0.2526x253.4 = 64.00 g

    The molar mass are: C = 12 g/mol, H 1 g/mol, S = 32 g/mol, and O = 16 g/mol

    So, to know how much moles will be, just divide the mass calculated above for the molar mass:

    C: 132.12/12 = 11 moles

    H: 25.20 / 1 = 25 moles

    S: 32.08/32 = 1 mol

    O: 64.00/16 = 4 moles

    So the molecular formula is C11H25SO4
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