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7 May, 22:10

Assuming dopant atoms are uniformly distributed in a silicon crystal, how far apart are these atoms when the doping concentrations are 5.0x1015 cm-3 and 5.0x1020 cm-3?

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  1. 7 May, 23:48
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    d = ~ 5.8μm

    d = ~ 0.13 μm

    Explanation:

    when the doping concentrations are 5 * 10^15 cm^-3

    d = v^-1/3; where d represent the distance between the atoms, and v represent the volume

    d = 1 / ∛v

    d = 1 / ∛5 * 10^15

    d = 1 / 170997.5

    d = 5.85 * 10 ^ - 6

    d = ~ 5.8μm

    when the doping concentrations are 5 * 10^20 cm^-3

    d = v^-1/3; where d represent the distance between the atoms, and v represent the volume

    d = 1 / ∛v

    d = 1 / ∛5 * 10^20

    using the principle of surds and standard forms, we have

    d = 1 / ∛0.5 * 10^21

    d = 1/7937005.26

    d = 1.26 * 10 ^ - 7

    d = 0.126 * 10 ^ - 6

    d = ~ 0.13 μm
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