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7 May, 22:48

Some amount of water is evaporated from a 2.0 L, 0.2 M NaI solution, to from a 1.0 L solution. The molar mass of NaI is 150 g/mol. What is the final concentration of NaI solution in

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  1. 8 May, 02:30
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    The final concentration of NaI is 0.4M

    Explanation:

    Step 1: Data given

    Initial volume of a 0.2 M NaI solution

    To form a 1.0 L solution

    The molar mass of NaI is 150 g/mol

    Step 2: Calculate the moles of NaI

    Moles NaI = 0.2M * 2.0 L = 0.4 moles

    Step 3: Calculate the final concentration

    Concentration = moles / volume

    Concentration = 0.4 moles / 1.0L

    Concentration = 0.4M

    The final concentration of NaI is 0.4M
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