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23 May, 09:46

As a result of the interaction of 22 g of higher oxide of the element of the main subgroup of group IV with water, 31 g of acid was formed. Set the name of an unknown chemical element.

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  1. 23 May, 13:36
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    Carbon (C)

    Explanation:

    Because the element is the element of the main subgroup of group IV, it has oxidation number + 4 in the oxide, and oxide formula is EO2.

    reaction:

    EO2 + H2O - --> H2EO3

    from reaction 1 mol 1 mol 1 mol

    31 g acid - 22 g oxide = 9 g water

    M (H2O) = 18 g/mol

    9g * 1 mol/18 g = 0.5 mol H2O

    As we see from reaction molar ratios EO2 : H2O : H2EO3 = 1 : 1 : 1,

    so if we have 0.5 mol H2O, we also have 0.5 mol EO2.

    0.5 mol EO2 has mass 22 g.

    Molar mass (EO2) = mass / number of moles = 22 g / 0.5 mol = 44 g/mol

    Molar mass (EO2) = M (E) + 2M (O) = 44 g/mol

    M (E) + 2 * 16 g/mol = 44 g/mo

    M (E) = 44-32 = 12 g/mol

    Molar mass 12 g / mol is molar mass of carbon.

    So, element is carbon (C).
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