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11 June, 16:00

A solution is made by dissolving 10.7 g of magnesium sulfate, MgSO4, in enough water to make exactly 100 mL of solution. Calculate the concentration (molarity) of MgSO4 in mmol/L (M).

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  1. 11 June, 17:36
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    [MgSO₄] = 890 mM/L

    Explanation:

    In order to determine molarity we need to determine the moles of solute that are in 1L of solution.

    Solute: MgSO₄ (10.7 g)

    Solvent: water

    Solution: 100 mL as volume. (100 mL. 1L / 1000mL) = 0.1L

    We convert the solute's mass to moles → 10.7 g / 120.36 g/mol = 0.089 moles

    Molarity (mol/L) → 0.089 mol/0.1L = 0.89 M

    In order to calculate M to mM/L, we make this conversion:

    0.89 mol. 1000 mmoles / 1 mol = 890 mmoles
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