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19 July, 15:36

What mass of HCl is needed to prepare 1.00 mole of Cl₂? 2 KMnO₄ + 16 HCl → 2MnCl₂ + 5 Cl₂ + 8 H₂O + 2 KCl

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  1. 19 July, 17:21
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    117 g HCl

    Explanation:

    use a molar ratio to cancel out the moles of Cl2

    1.00 mol Cl2 x 16 mol HCl / 5 mol Cl2

    multiply by the molar mass of HCl to get the mass of the HCl

    3.2 mol HCl x 36.46 g HCl

    then you should get around

    116.672 g HCl
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