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1 February, 21:22

A solution is prepared by dissolving 38.6 g sucrose (C12H22O11) in 495 g of water. Determine the mole fraction of sucrose if the final volume of the solution is 508 mL.

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  1. 2 February, 00:57
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    4.09*10⁻³ is the mole fraction of sucrose

    Explanation:

    Mole fraction = Moles of solute or solvent / Total moles

    Let's convert the mass to moles (mass / molar mass)

    38.6 g / 342 g/m = 0.113 moles of sucrose

    495 g / 18 g/m = 27.5 moles of water

    Total moles = 0.113 m + 27.5 m = 27.0613 moles

    Mole fraction of sucrose = Moles of sucrose / Total moles

    0.113 m / 27.0613 moles = 4.09*10⁻³
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