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29 January, 03:24

A 8.46 L sample oxygen gas at 267K and 1.23 atm is heated to 295K. If the volume changes to 6.98L, what is the new pressure?

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  1. 29 January, 06:39
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    The new pressure is 1,65 atm

    Explanation:

    We use the gas formula, which results from the combination of the Boyle, Charles and Gay-Lussac laws. According to which at a constant mass, temperature, pressure and volume vary, keeping constant PV / T.

    (P1xV1) / T1 = (P2xV2) / T2

    (1,23atmx 8,46L) / 267 K = (P2 x 6,98L) / 295K

    0,039 atmx L/K = (P2 x 6,98L) / 295K

    P2 = (0,039 atmx L/K) x 295K/6,98L = 1,65 atm
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