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17 October, 03:38

How much water should be added to 85 mL of 0.45 M HCI to reduce the concentration to 0.20 M?

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  1. 17 October, 05:31
    0
    106.25 mL

    Explanation:

    For this, we can use

    C1*V1=C2*V2

    C1 = 0.45

    V1 = 85

    C2 = 0.20

    V2=?

    0.45 * 85 = 0.20 * V2

    V2 = (0.45 * 85) / 0.20

    V2=191.25mL

    To find the amount of water added, subtract V1 from V2

    191.25 - 85 = 106.25mL
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