How much heat energy in megajoules is needed to convert 7 kg of ice at - 9 seat to water at 0C

Q = 131670 * 10⁻⁶ MJ

Explanation:

Given dа ta:

Mass of ice = 7 Kg

Initial temperature = - 9 °C (-9+273 = 264 k)

Final temperature = 0°C (0 + 273 = 273 k)

Heat absorbed = ?

Solution:

Q = m. c. ΔT

Specific heat capacity of ice is 2090 j/Kg. K

ΔT = T2 - T1

ΔT = 273 k - 264 k

ΔT = 9 k

Q = m. c. ΔT

Q = 7kg. 2090 j/Kg. K. 9 k

Q = 131670 j

Q = 131670 / 10⁶ MJ

Q = 131670 * 10⁻⁶ MJ