If the theoretical yield of the reaction below corresponds to 25.3 g and the percent yield of the reaction is known to be reproducibly 81.1%, calculate the actual yield. Given: Li2O + H2O → 2 LiOH

Actual yield = 20.52 g

Explanation:

Given dа ta:

Theoretical yield = 25.3 g

Percentage yield = 81.1 %

Actual yield = ?

Solution:

Formula:

Percentage yield = Actual yield / theoretical yield * 100

81.1 % / 100 = Actual yield / 25.3 g

0.811 = Actual yield / 25.3 g

Actual yield = 0.811 * 25.3 g

Actual yield = 20.52 g