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27 February, 17:10

13. Base your answer to the following question on the information below and you knowledge of chemistry,

A 100.-gram sample of liquid water is heated from 20.0°C to 50.0°C. Enough KCION (S) is dissolved

in the sample of water at 50.0°C to form a saturated solution.

Using the information on Table B, determine the amount of heat absorbed by the water

when the water is heated from 20.0°C to 50.0°C.

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Answers (1)
  1. 27 February, 18:23
    0
    Heat absorbed by water is 12540 J

    Explanation:

    Given dа ta:

    Mass of water = 100 g

    Temperature changes = 20.0°C to 50.0°C

    Heat absorbed by water = ?

    Solution:

    Specific heat of water is 4.18 j/g.°C

    Formula:

    Q = m. c. ΔT

    Q = amount of heat absorbed or released

    m = mass of given substance

    c = specific heat capacity of substance

    ΔT = change in temperature

    ΔT = 50.0°C - 20.0°C

    ΔT = 30.0°C

    Q = m. c. ΔT

    Q = 100 g. 4.18 j/g.°C. 30.0°C

    Q = 12540 J

    Heat absorbed by water is 12540 J.
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