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20 April, 19:35

75 mL of water is added to a 360 mL solution of acetic acid with a concentration of 0.87 M. Determine the molarity of the new solution.

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  1. 20 April, 21:42
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    The molarity of the new solution is 0.72 M

    Explanation:

    Step 1: Data given

    Volume of the original solution = 360 mL =.360 L

    Molarity = 0.87 M

    We add 75 mL = 0.075 L

    Step 2: Calculate moles

    Moles = molarity * volume

    Moles = 0.87 M * 0.360 L

    Moles = 0.3132 moles

    Step 3: Calculate new molarity

    The number of moles stays constant

    Molarity = moles / volume

    Molarity = 0.3132 moles / (0.36+0.075)

    Molarity = 0.3132 moles / 0.435 L

    Molarity = 0.72 M

    The molarity of the new solution is 0.72 M
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