KHP is a monoprotic acid which provides one H + ion. How would your results be affected if a diprotic acid (such as sulfuric acid, H2SO4) was used which provides two H + ions? Calculate the molarity of the NaOH solution if 17.50 mL of N a O H was titrated against 10.50 mL of 0.75 M H2SO4.

Question

Chemistry

Cherokee

18 July, 16:08

KHP is a monoprotic acid which provides one H + ion. How would your results be affected if a diprotic acid (such as sulfuric acid, H2SO4) was used which provides two H + ions? Calculate the molarity of the NaOH solution if 17.50 mL of N a O H was titrated against 10.50 mL of 0.75 M H2SO4.

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Cutie Pie · Answer 1

A.

In a diprotic acid, 2 moles of H + ions is released. Therefore, number of moles of H + in a diprotic acid = 2 * number of moles of H + of monoprotic acid.

B.

Equation of the reaction

2NaOH + H2SO4 - -> Na2SO4 + 2H2O

Number of moles of H2SO4 = molar concentration * volume

= 0.75 * 0.0105

= 0.007875 moles.

By stoichiometry, since 1 mole of H2SO4 reacts with 2 moles of NaOH. Therefore, number of moles of NaOH = 2 * 0.007875

= 0.01575 moles.

Molar concentration of NaOH = number of moles : volume

= 0.01575 : 0.0175

= 0.9 M of NaOH.