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18 July, 16:08

KHP is a monoprotic acid which provides one H + ion. How would your results be affected if a diprotic acid (such as sulfuric acid, H2SO4) was used which provides two H + ions? Calculate the molarity of the NaOH solution if 17.50 mL of N a O H was titrated against 10.50 mL of 0.75 M H2SO4.

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  1. 18 July, 19:25
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    A.

    In a diprotic acid, 2 moles of H + ions is released. Therefore, number of moles of H + in a diprotic acid = 2 * number of moles of H + of monoprotic acid.

    B.

    Equation of the reaction

    2NaOH + H2SO4 - -> Na2SO4 + 2H2O

    Number of moles of H2SO4 = molar concentration * volume

    = 0.75 * 0.0105

    = 0.007875 moles.

    By stoichiometry, since 1 mole of H2SO4 reacts with 2 moles of NaOH. Therefore, number of moles of NaOH = 2 * 0.007875

    = 0.01575 moles.

    Molar concentration of NaOH = number of moles : volume

    = 0.01575 : 0.0175

    = 0.9 M of NaOH.
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