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Chemistry
Enrique Mendoza
5 December, 03:28
How many atoms are in 36.1 g of boron
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Isaac Travis
5 December, 04:01
0
The answer is 2.011 * 10^24
Explanation:
Looking for atoms in boron,
Molar mass of B = 10.81g/mol
There is 36.1g of B,.
Using avogadro constant = 6.023 * 10^23
36.1g of B = 6.023 * 10^23/10.81 * 36.1g
That is, 6.023*10^23 divided by 10.81 multiplied by 36.1g
From this calculation, we get
36.1g of boron = 2.011 * 10^24atoms.
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