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17 March, 00:03
Molarity of 82.6 g sucrose, C12H22O11, in 725 mL
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Brenden Patel
17 March, 00:52
0
0.33 M
Explanation:
Given dа ta:
Mass of sucrose = 82.6 g
Volume = 725 mL
Molarity = ?
Solution:
725/1000 = 0.725 L
Molarity = number of moles of solute / volume in litter
Number of moles of sucrose:
Number of moles = mass/molar mass
Number of moles = 82.6 g / 342.3 g/mol
Number of moles = 0.24 mol
Molarity = number of moles of solute / volume in litter
Molarity = 0.24 mol / 0.725 L
Molarity = 0.33 M
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