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17 March, 00:18

What is the ph of a solution if [oh-] = 2.3 x 10-5 m?

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  1. 17 March, 03:40
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    POH = - log[OH-] and pH + pOH = 14

    So, all you have to do is take the negative log of 2.3*10^-5 and then subtract that number from 14 to find the pH
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