How many liters of gaseous hydrogen bromide at 58°C and 0.891 atm will a chemist need if she wishes to prepare 3.50 L of 1.20 M hydrobromic acid?

We need 128 liters of a gaseous hydrogen bromide

Explanation:

Step 1:

Temperature = 58°C

Pressure = 0.891 atm

Volume ofHydrobromic acid we want to prepare is 3.50 L (1.20M)

Step 2: Calculate moles HBr

Moles HBr = molarity * volule

Moles HBr = 1.20 * 3.50 L

Moles HBr = 4.20 moles HBr

Step 3: Calculate volume of Hydrogen bromide

pV = nRT

V = (nRT) / P

⇒ with V = the volume of gaseous hydrogen bromide = ?

⇒with p = the pressure of the gas = 0.891 atm

⇒ with n = the number of moles of hydrogen bromide = 4.2 moles

⇒ with R = the gasconstant = 0.08206 L*atm / mol*K

⇒ with T = the temperature = 58.0 °C = 273 + 58 = 331 Kelvin

V = (4.2*0.08206*331) / 0.891

V = 128 L

We need 128 liters of a gaseous hydrogen bromide

15.4 l