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23 January, 09:24

How many grams of potassium chloride are required to make 250 ml of a 0.75 m kcl solution?

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  1. 23 January, 11:37
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    The solution would need 13.9 g of KCl

    Explanation:

    0.75 m, means molal concentration

    0.75 moles in 1 kg of solvent.

    Let's think as an aqueous solution.

    250 mL = 250 g, cause water density (1g/mL)

    1000 g have 0.75 moles of solute

    250 g will have (0.75. 250) / 1000 = 0.1875 moles of KCl

    Let's convert that moles in mass (mol. molar mass)

    0.1875 m. 74.55 g/m = 13.9 g
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