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5 March, 00:50

What's the molarity of the solution containing 10 g of NaCN in 250 mL of solution?

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  1. 5 March, 04:24
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    0.816

    Explanation:

    1 mole of NaCN is

    Na = 23

    C = 12

    N = 14

    Total = 49 grams / mole (just add 23 + 12 + 14)

    moles when only 10 grams of NaCN are used.

    moles = grams/molar mass

    grams = 10

    molar mass = 49

    moles = 10 / 49

    moles = 0.204 moles

    Volume in Liters

    250 mL = 250mL/1000 mL / Liter = 0.25 Liters

    Molarity

    M = m/V

    M = 0.204/0.25 = 0.816
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