What is the temperature of 13.3 moles of carbon dioxide that occupies 6 m3 and applies a pressure of 23 kPa to its container?

T = 1248 K

Explanation:

We can calculate the T, by using the ideal gas law:

PV = nRT

Where we have:

The pressure P, volume V, and temperature T, R is the gas constant, and n is the number of moles of the gas.

According to the international unit systems R is 8.314 J / (K·mol)

With this value the P unit will be Pa and the V unit will be m³.

Then,

T = PV / nR

T = (23 * 1000 * 6) / (13.3 * 8.314)

T = 1248 K