Ask Question
16 July, 04:53

Describe how to write the Keq expression for the following reaction. 2NH3 (g) 3H2 (g) + N2 (g)

+2
Answers (2)
  1. 16 July, 05:15
    0
    2NH3 (g) - -> 3H2 (g) + N2 (g)

    The equlibrium constant is the ratio of the concentration of products to that of reactants.

    Keq = [Products] / [Reactants]

    So to write the expression, we have to identify our reactants and products.

    Reactants = NH3

    Products = H2 and N2

    The coefficients are expressed as powers of the entities in the expression, this leads us to;

    [Products] = [H2]² [ N2]

    [Reactants] = [NH3]³

    Keq = [NH3]³ / [H2]² [ N2]
  2. 16 July, 06:09
    0
    Pure solids and pure liquids are not included in the equilibrium constant expression.

    Since all reactants and products are gases, they are all included in the equilibrium constant expression.

    Write the concentrations of the products in the numerator (top) and the reactants in the denominator of the fraction.

    Raise the concentrations to the correct power, based on the coefficients.

    Write the expression as

    Explanation:

    edg2020

    included statements
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “Describe how to write the Keq expression for the following reaction. 2NH3 (g) 3H2 (g) + N2 (g) ...” in 📙 Chemistry if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers