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15 October, 22:31

Solution X is 10 percent alcohol by volume, and solution Y is 30 percent alcohol by volume. How many milliliters of solution Y must be added to 200 milliliters of solution X to create a solution that is 25 percent alcohol by volume?

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  1. 16 October, 01:44
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    600 mL

    Explanation:

    The volume of 10% acid solution used to make the mixture = 200 L

    Let the volume of 30% acid solution used to make the mixture = x mL

    Total volume of the mixture = (200 + x) mL

    For 10% acid solution:

    C₁ = 10%, V₁ = 200 mL

    For 30% acid solution:

    C₂ = 30%, V₂ = x mL

    For the resultant solution of sulfuric acid:

    C₃ = 25%, V₃ = (200 + x) mL

    Using

    C₁V₁ + C₂V₂ = C₃V₃

    10*200 + 30*x = 25 * (200 + x)

    Solving for x,

    x = 600 mL

    600 milliliters of solution Y must be added to 200 milliliters of solution X to create a solution that is 25 percent alcohol by volume.
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