a spherical weather balloon has volume of 12.0 L when inflated in STP. Assuming it could stay anchored and intact as a hurricane passed overhead lowering the pressure to 720.0 mm Hg what would be the new volume of the balloon assuming the temperature stays at 0 C?

V₂ = 12.63 L

Explanation:

Given dа ta:

Initial volume of balloon = 12.0 L

Initial temperature = standard = 273 K

Initial pressure = standard = 1 atm

Final pressure = 720.0 mmHg (720/760 = 0.95 atm)

Final volume = ?

Final temperature = 0°C (273 k)

Solution:

Formula:

P₁V₁/T₁ = P₂V₂/T₂

P₁ = Initial pressure

V₁ = Initial volume

T₁ = Initial temperature

P₂ = Final pressure

V₂ = Final volume

T₂ = Final temperature

Solution:

V₂ = P₁V₁ T₂ / T₁ P₂

V₂ = 1 atm * 12.0 L * 273 K / 273 K * 0.95 atm

V₂ = 3276 atm. L. K / 259.35 k. atm

V₂ = 12.63 L