It is necessary to make 500 mL of a 0.375 M solution of hydrochloric acid (HCl) using distilled water and full strength hydrochloric acid (M=12.0). what volume of the full strength HCl and what volume of water are necessary to make the desired solution?

15.625 mL

Explanation:

To solve this problem, we have to make use of the dilution formula. By so doing we can obtain the volume of stock solution that should be required to prepare the specified concentration and volume of the dilute acid as shown in the given question.

The dilution formula is;

C1V1 = C2V2

Where;

C1 = concentration of stock solution = 12.0 M

V1 = volume of stock solution = ?

C2 = concentration of dilute solution = 0.375 M

V2 = volume of dilute solution = 500 mL

Making V1 the subject of the formula;

V1 = C2V2/C1

V1 = 0.375 * 500 / 12.0

V1 = 15.625 mL

Therefore, 15.625 mL of stock solution is required.