At 823 °C, Kp = 490 for the equilibrium reaction CoO (s) + CO (g) ⟷ Co (s) + CO2 (g) What is the value of Kc at the same temperature for the equilibrium below? Co (s) + CO2 (g) ⟷ CoO (s) + CO (g)

490

Explanation:

823°C = (823 + 273) K = 1096K

Kp = Kc (RT) ∇ⁿ

∇ⁿ = change in mole in product - change in mole in reactant.

Equation of reaction;

Co (s) + CO2 (g) ⟷ CoO (s) + CO (g)

∇ⁿ = 2 - 2 = 0

Kp = Kc * (RT) ∇ⁿ

Kp = Kc when ∇ⁿ = 0

Since anything or number raised to power of 0 = 1

Kp = 490 = Kc

Kc = 490.