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27 June, 19:06

A 3.00 L flask contains 2.33 g of argon gas at 312 mm Hg What is the temperature of the gas

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  1. 27 June, 19:55
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    T = 257.36 k

    Explanation:

    using the ideal gas law

    pv=nRt

    first, convert pressure from mmhg to kpa

    312 x (101.3/760) = 41.58 kpa

    R is constant = 8.31

    to get n (number of moles)

    n=m/M (m is mass, M is molar mass)

    molar mass of argon is 39.948

    n = 2.33/39.948

    n=0.0583

    substitute;

    41.58 x 3 = 0.0583 x 8.31 x T

    T = (41.58 x 3) / (0.0583 x 8.31)

    T = 257.36 k
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