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12 September, 23:00

You have 100 mL of a 12M solution of HCl, and you need to dilute it to 1.5M for an experiment. How many liters will your new solution be?

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  1. 13 September, 00:46
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    800.0 mL.

    Explanation:

    To solve this problem; we must mention the rule states the no. of millimoles of a substance before and after dilution is the same.

    (MV) before dilution of HCl = (MV) after dilution of HCl

    M before dilution = 12.0 M, V before dilution = 100.0 mL.

    M after dilution = 1.5 M, V after dilution = ? mL.

    ∵ (MV) before dilution of HCl = (MV) after dilution of HCl

    ∴ (12.0 M) (100.0 mL) = (1.5 M) (V after dilution of HCl)

    ∴ V after dilution of HCl = (12.0 M) (100.0 mL) / (1'.5 M) = 800.0 mL.
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