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26 September, 19:40

You need to make an aqueous solution of 0.125 M barium chloride for an experiment in lab, using a 250 mL volumetric flask. How much solid barium chloride should you add?

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  1. 26 September, 23:25
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    6.51g

    Explanation:

    0.125 M = 0.125 mol/1000ml

    0.125/4 = 0.03125 mol

    BaCl2:

    Mr = 137.3 + 2 (35.5) = 208.3

    mass = 208.3 (0.03125) = 6.509375
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