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5 August, 10:22

What is the temperature of 100 liter container having 1 mole of an

ideal gas at a pressure of 20 kilopascals

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Answers (1)
  1. 5 August, 11:09
    0
    Answer:-

    240.558 K

    Explanation:-

    Number of Moles n = 1

    Pressure P = 20 kilopascals = 20 KPa

    Volume V = 100 L

    We know Universal Gas constant R = 8.314 L kPa K-1 mol-1

    Using the relation

    PV = nRT

    Temperature T = P x V / (n x R)

    T = 20 KPa x 100 L / (1 mol x 8.314 L kPa K-1 mol-1)

    = 240.558 K
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