Calculate the concentration of oxalate ion (c2o42-) in a 0.175 m solution of oxalic acid (c2h2o4). [for oxalic acid, ka1 = 6.5 * 10-2, ka2 = 6.1 * 10-5.]

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Chemistry

Jazlene Fry

19 June, 23:54

Calculate the concentration of oxalate ion (c2o42-) in a 0.175 m solution of oxalic acid (c2h2o4). [for oxalic acid, ka1 = 6.5 * 10-2, ka2 = 6.1 * 10-5.]

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Zavala · Answer 1

C2H2O4 C2HO4 - + H+

0.175 - x x x + y

C2HO4 - c2o42 - + H+

x - y y x + y

K2 = (y) (x + y) / (x-y)

As, y << x

So, K2 = (y) (x) / (x)

K2 = y = 6.1 * 10^-5

Hence, concentration of (c2o42-) 6.1 * 10^-5 M