How many grams of sodium chloride can be produced from 46.3 g of sodium hydroxide?

=67.65 grams of sodium chloride.

Explanation:

In this explanation, we shall assume that the limiting reagent was NaOH only and the amount of HCl used was sufficient.

NaOH + HCl → NaCl + H₂O

In the equation, the ratio of NaOH used to the NaCl produced will be 1:1

The number of moles of NaOH in 46.3 g.

Number of moles = mass/RMM

=46.3g/40g/mol

=1.1575 moles.

Since the reaction ratio is 1:1, the Number of moles of NaCl produced is also 1.1575 moles.

The mass of 1.1575 moles of NaCl is: 1.1575 moles * 58.443g/mol

=67.65 grams of sodium chloride.