Carbon disulfide burns in oxygen to yield carbon dioxide and sulfur dioxide according to the chemical equation cs2 (ℓ) + 3 o2 (g) - → co2 (g) + 2 so2 (g). if 1.25 mol of cs2 is combined with 0.57 mol of o2, identify the limiting reactant.

Question

Chemistry

Zavier Shepard

10 July, 19:16

Carbon disulfide burns in oxygen to yield carbon dioxide and sulfur dioxide according to the chemical equation cs2 (ℓ) + 3 o2 (g) - → co2 (g) + 2 so2 (g). if 1.25 mol of cs2 is combined with 0.57 mol of o2, identify the limiting reactant.

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Answers (1)

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Marlene Kemp · Answer 1

oxygen is the limiting reagent

Explanation:

cs2 (ℓ) + 3 o2 (g) - → co2 (g) + 2 so2 (g)

from the balanced equation

1 mole carbon disulfide requires 3 mole of oxygen

1.25 moles of cs₂ will required 3.75 mole of oxygen

while 0.57 mole of oxygen will require 0.19 mole of cs₂

comparing, oxygen is the limiting reagent since 0.57 mole of oxygen will require just 0.19 mole out of 1.25 mole meaning cs₂ is in excess.