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16 August, 19:22

What is the empirical formula of a compound composed of 30.5 g potassium (k) and 6.24 g oxygen (o) ?

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  1. 16 August, 23:10
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    The empirical formula of the compound is K₂O.

    Step 1. Calculate the moles of each element

    The empirical formula is the simplest whole-number ratio of atoms in a compound.

    The ratio of atoms is the same as the ratio of moles.

    So, our job is to calculate the molar ratio of K to O.

    Moles of K = 30.5 g K * (1 mol K / (39.10 g K) = 0.7801 mol K

    Moles of O = 6.24 g O * (1 mol O/16.00 g O) = 0.3900 mol O

    Step 2. Calculate the molar ratio of the elements

    Divide each number by the smallest number of moles

    Ni:F = 0.1552:0.3100 = 2.001:1 ≈ 2:1

    Step 3: Write the empirical formula

    EF = K₂O
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