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24 June, 14:43

45.0 mL of a Naoh solution is titrated with 0.12 M HCl. If 29.6 mL is required for neutralization,

what is the concentration of the NaOH solution?

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  1. 24 June, 16:01
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    M (NaOH) = 0.0789 M

    Explanation:

    NaOH + HCl - --> NaCl + H2O

    M (NaOH) * V (NaOH) = M (HCl) * V (HCl)

    M (NaOH) * 45.0 mL (NaOH) = 0.12 M (HCl) * 29.6 mL (HCl)

    M (NaOH) = 0.12*29.6/45.0 = 0.0789 M
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