What is the energy of light with a wavelength of 468 nm? (The speed of light in a vacuum is 3.00 x 10^8m/s, and Planck's constant is 6.626 x 10^-34J·s.)

A. 2.35 x 10^27J

B. 4.25 x 10^-28mJ

C. 2.35 x 10^18J

D. 4.25 x 10^-19J

The answer for the problem is explained below.

The option for the answer is "D".

Therefore the energy of the light is 4.25 * 10^-19 J

Explanation:

Given:

wavelength (λ) = 468 nm = 468*10^-9 m

speed of light (c) = 3.00 x 10^8m/s

Planck's constant is 6.626 x 10^-34J·s

To solve:

energy of light (E)

We know,

E = (h*c) : λ

E = (6.626 x 10^-34 * 3.00 x 10^8) : 468*10^-9

E = 4.25 * 10^-19 J

Therefore the energy of the light is 4.25 * 10^-19 J